JEE Math Practice Question

Let y = y(x) be a solution curve of the differential equation $$(y + 1){\tan ^2}x\,dx + \tan x\,dy + y\,dx = 0$$, $$x \in \left( {0,{\pi \over 2}} \right)$$. If $$\mathop {\lim }\limits_{x \to 0 + } xy(x) = 1$$, then the value of $$y\left( {{\pi \over 4}} \right)$$ is :

1. A.$$ - {\pi \over 4}$$
2. B.$${\pi \over 4} - 1$$
3. C.$${\pi \over 4} + 1$$
4. D.$${\pi \over 4}$$