JEE Math Practice Question
Let y = y(x) be solution of the differential equation $${\log _{}}\left( {{{dy} \over {dx}}} \right) = 3x + 4y$$, with y(0) = 0. If $$y\left( { - {2 \over 3}{{\log }_e}2} \right) = \alpha {\log _e}2$$, then the value of $$\alpha$$ is equal to :
- A.$$ - {1 \over 4}$$
- B.$${1 \over 4}$$
- C.$$2$$
- D.$$ - {1 \over 2}$$
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