JEE Math Practice Question

Let y = y(x) be the solution of the differential equation $${{dy} \over {dx}} = (y + 1)\left( {(y + 1){e^{{x^2}/2}} - x} \right)$$, 0 < x < 2.1, with y(2) = 0. Then the value of $${{dy} \over {dx}}$$ at x = 1 is equal to :

1. A.$${{{e^{5/2}}} \over {{{(1 + {e^2})}^2}}}$$
2. B.$${{5{e^{1/2}}} \over {{{({e^2} + 1)}^2}}}$$
3. C.$$ - {{2{e^2}} \over {{{(1 + {e^2})}^2}}}$$
4. D.$${{ - {e^{3/2}}} \over {{{({e^2} + 1)}^2}}}$$