JEE Math Practice Question
If the curve y = y(x) is the solution of the differential equation $$2({x^2} + {x^{5/4}})dy - y(x + {x^{1/4}})dx = {2x^{9/4}}dx$$, x > 0 which passes through the point $$\left( {1,1 - {4 \over 3}{{\log }_e}2} \right)$$, then the value of y(16) is equal to :
- A.$$4\left( {{{31} \over 3} - {8 \over 3}{{\log }_e}3} \right)$$
- B.$$\left( {{{31} \over 3} - {8 \over 3}{{\log }_e}3} \right)$$
- C.$$\left( {{{31} \over 3} + {8 \over 3}{{\log }_e}3} \right)$$
- D.$$4\left( {{{31} \over 3} + {8 \over 3}{{\log }_e}3} \right)$$
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