JEE Math Practice Question
If y = y(x) is the solution of the differential equation $${{dy} \over {dx}}$$ + (tan x) y = sin x, $$0 \le x \le {\pi \over 3}$$, with y(0) = 0, then $$y\left( {{\pi \over 4}} \right)$$ equal to :
- A.$${1 \over 2}$$loge 2
- B.$$\left( {{1 \over {2\sqrt 2 }}} \right)$$ loge 2
- C.loge 2
- D.$${1 \over 4}$$ loge 2
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