JEE Math Practice Question
If y = y(x) is the solution of the differential equation, $${{dy} \over {dx}} + 2y\tan x = \sin x,y\left( {{\pi \over 3}} \right) = 0$$, then the maximum value of the function y(x) over R is equal to:
- A.$${1 \over 8}$$
- B.8
- C.$$-$$$${15 \over 4}$$
- D.$${1 \over 2}$$
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