JEE Math Practice Question
If y = y(x) is the solution of the differential equation, $${e^y}\left( {{{dy} \over {dx}} - 1} \right) = {e^x}$$ such that y(0) = 0, then y(1) is equal to:
- A.2 + loge2
- B.loge2
- C.1 + loge2
- D.2e
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