JEE Math Practice Question
Let y = y(x) be the solution curve of the differential equation, $$\left( {{y^2} - x} \right){{dy} \over {dx}} = 1$$, satisfying y(0) = 1. This curve intersects the x-axis at a point whose abscissa is :
- A.2 + e
- B.-e
- C.2
- D.2 - e
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