JEE Math Practice Question
Let y = y(x) be the solution of the differential equation, $${{2 + \sin x} \over {y + 1}}.{{dy} \over {dx}} = - \cos x$$, y > 0,y(0) = 1. If y($$\pi $$) = a and $${{dy} \over {dx}}$$ at x = $$\pi $$ is b, then the ordered pair (a, b) is equal to :
- A.(2, 1)
- B.$$\left( {2,{3 \over 2}} \right)$$
- C.(1, -1)
- D.(1, 1)
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