JEE Math Practice Question
If a curve y = f(x), passing through the point (1, 2), is the solution of the differential equation, 2x2dy= (2xy + y2)dx, then $$f\left( {{1 \over 2}} \right)$$ is equal to :
- A.$${1 \over {1 - {{\log }_e}2}}$$
- B.$${1 \over {1 + {{\log }_e}2}}$$
- C.$${{ - 1} \over {1 + {{\log }_e}2}}$$
- D.$${1 + {{\log }_e}2}$$
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