JEE Math Practice Question

Let y = y(x) be the solution of the differential equation, xy'- y = x2(xcosx + sinx), x > 0. if y ($$\pi $$) = $$\pi $$ then $$y''\left( {{\pi \over 2}} \right) + y\left( {{\pi \over 2}} \right)$$ is equal to :

1. A.$$1 + {\pi \over 2}$$
2. B.$$2 + {\pi \over 2} + {{{\pi ^2}} \over 4}$$
3. C.$$2 + {\pi \over 2}$$
4. D.$$1 + {\pi \over 2} + {{{\pi ^2}} \over 4}$$