JEE Math Practice Question

Let y = y(x) be the solution of the differential equation cosx$${{dy} \over {dx}}$$ + 2ysinx = sin2x, x $$ \in $$ $$\left( {0,{\pi \over 2}} \right)$$. If y$$\left( {{\pi \over 3}} \right)$$ = 0, then y$$\left( {{\pi \over 4}} \right)$$ is equal to :

1. A.$${1 \over {\sqrt 2 }} - 1$$
2. B.$${\sqrt 2 - 2}$$
3. C.$${2 - \sqrt 2 }$$
4. D.$${2 + \sqrt 2 }$$