JEE Math Practice Question
If $${{dy} \over {dx}} + {3 \over {{{\cos }^2}x}}y = {1 \over {{{\cos }^2}x}},\,\,x \in \left( {{{ - \pi } \over 3},{\pi \over 3}} \right)$$ and $$y\left( {{\pi \over 4}} \right) = {4 \over 3},$$ then $$y\left( { - {\pi \over 4}} \right)$$ equals -
- A.$${1 \over 3} + {e^6}$$
- B.$${1 \over 3}$$
- C.$${1 \over 3}$$ + e3
- D.$$-$$ $${4 \over 3}$$
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