JEE Math Practice Question

The solution of the differential equation, $${{dy} \over {dx}}$$ = (x – y)2, when y(1) = 1, is :

1. A.$$-$$ loge $$\left| {{{1 + x - y} \over {1 - x + y}}} \right|$$ = x + y $$-$$ 2
2. B.loge $$\left| {{{2 - x} \over {2 - y}}} \right|$$ = x $$-$$ y
3. C.loge $$\left| {{{2 - y} \over {2 - x}}} \right|$$ = 2(y $$-$$ 1)
4. D.$$-$$ loge $$\left| {{{1 - x + y} \over {1 + x - y}}} \right|$$ = 2(x $$-$$ 1)