JEE Math Practice Question
Let y = y(x) be the solution of the differential equation, x$${{dy} \over {dx}}$$ + y = x loge x, (x > 1). If 2y(2) = loge 4 $$-$$ 1, then y(e) is equal to :
- A.$$ - {e \over 2}$$
- B.$$ - {{{e^2}} \over 2}$$
- C.$${{{e^2}} \over 4}$$
- D.$${e \over 4}$$
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