JEE Math Practice Question

The solution of the differential equation $$x{{dy} \over {dx}} + 2y$$ = x2 (x $$ \ne $$ 0) with y(1) = 1, is :

1. A.$$y = {4 \over 5}{x^3} + {1 \over {5{x^2}}}$$
2. B.$$y = {3 \over 4}{x^2} + {1 \over {4{x^2}}}$$
3. C.$$y = {{{x^2}} \over 4} + {3 \over {4{x^2}}}$$
4. D.$$y = {{{x^3}} \over 5} + {1 \over {5{x^2}}}$$