JEE Math Practice Question

If y = y(x) is the solution of the differential equation $${{dy} \over {dx}} = \left( {\tan x - y} \right){\sec ^2}x$$, $$x \in \left( { - {\pi \over 2},{\pi \over 2}} \right)$$, such that y (0) = 0, then $$y\left( { - {\pi \over 4}} \right)$$ is equal to :

1. A.$${1 \over 2} - e$$
2. B.$$e - 2$$
3. C.$$2 + {1 \over e}$$
4. D.$${1 \over e} - 2$$