JEE Math Practice Question

The solution of the differential equation $${{dy} \over {dx}}\, + \,{y \over 2}\,\sec x = {{\tan x} \over {2y}},\,\,$$ where 0 $$ \le $$ x < $${\pi \over 2}$$, and y (0) = 1, is given by :

1. A.y = 1 $$-$$ $${x \over {\sec x + \tan x}}$$
2. B.y2 = 1 + $${x \over {\sec x + \tan x}}$$
3. C.y2 = 1 $$-$$ $${x \over {\sec x + \tan x}}$$
4. D.y = 1 + $${x \over {\sec x + \tan x}}$$