JEE Math Practice Question
If $$x{{dy} \over {dx}} = y\left( {\log y - \log x + 1} \right),$$ then the solution of the equation is :
- A.$$y\log \left( {{x \over y}} \right) = cx$$
- B.$$x\log \left( {{y \over x}} \right) = cy$$
- C.$$\log \left( {{y \over x}} \right) = cx$$
- D.$$\log \left( {{x \over y}} \right) = cy$$
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