JEE Math Practice Question
Solution of the differential equation $$ydx + \left( {x + {x^2}y} \right)dy = 0$$ is
- A.$$log$$ $$y=Cx$$
- B.$$ - {1 \over {xy}} + \log y = C$$
- C.$${1 \over {xy}} + \log y = C$$
- D.$$ - {1 \over {xy}} = C$$
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