JEE Math Practice Question
Let xk + yk = ak, (a, k > 0 ) and $${{dy} \over {dx}} + {\left( {{y \over x}} \right)^{{1 \over 3}}} = 0$$, then k is:
- A.$${1 \over 3}$$
- B.$${2 \over 3}$$
- C.$${4 \over 3}$$
- D.$${3 \over 2}$$
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