JEE Math Practice Question

If $$x = 2\sin \theta - \sin 2\theta $$ and $$y = 2\cos \theta - \cos 2\theta $$, $$\theta \in \left[ {0,2\pi } \right]$$, then $${{{d^2}y} \over {d{x^2}}}$$ at $$\theta $$ = $$\pi $$ is :

1. A.$${3 \over 8}$$
2. B.$${3 \over 2}$$
3. C.$${3 \over 4}$$
4. D.-$${3 \over 4}$$