JEE Math Practice Question
For x > 1, if (2x)2y = 4e2x$$-$$2y, then (1 + loge 2x)2 $${{dy} \over {dx}}$$ is equal to :
- A.$${{x\,{{\log }_e}2x - {{\log }_e}2} \over x}$$
- B.loge 2x
- C.x loge 2x
- D.$${{x\,{{\log }_e}2x + {{\log }_e}2} \over x}$$
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