JEE Math Practice Question

If $$2y = {\left( {{{\cot }^{ - 1}}\left( {{{\sqrt 3 \cos x + \sin x} \over {\cos x - \sqrt 3 \sin x}}} \right)} \right)^2}$$, x $$ \in $$ $$\left( {0,{\pi \over 2}} \right)$$ then $$dy \over dx$$ is equal to:

1. A.$$2x - {\pi \over 3}$$
2. B.$${\pi \over 6} - x$$
3. C.$${\pi \over 3} - x$$
4. D.$$x - {\pi \over 6}$$