JEE Math Practice Question
The product of all solutions of the equation $\mathrm{e}^{5\left(\log _{\mathrm{e}} x\right)^2+3}=x^8, x>0$, is :
- A.$e^2$
- B.$e$
- C.$\mathrm{e}^{6 / 5}$
- D.$\mathrm{e}^{8 / 5}$
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