JEE Math Practice Question
Two integers $$x$$ and $$y$$ are chosen with replacement from the set $$\{0,1,2,3, \ldots, 10\}$$. Then the probability that $$|x-y|>5$$, is :
- A.$$\frac{31}{121}$$
- B.$$\frac{60}{121}$$
- C.$$\frac{62}{121}$$
- D.$$\frac{30}{121}$$
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