JEE Math Practice Question
The mean and variance of a binomial distribution are $$\alpha$$ and $$\frac{\alpha}{3}$$ respectively. If $$\mathrm{P}(X=1)=\frac{4}{243}$$, then $$\mathrm{P}(X=4$$ or 5$$)$$ is equal to :
- A.$$\frac{5}{9}$$
- B.$$\frac{64}{81}$$
- C.$$\frac{16}{27}$$
- D.$$\frac{145}{243}$$
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