JEE Math Practice Question
If the sum and the product of mean and variance of a binomial distribution are 24 and 128 respectively, then the probability of one or two successes is :
- A.$$ \frac{33}{2^{32}} $$
- B.$$\frac{33}{2^{29}}$$
- C.$$\frac{33}{2^{28}}$$
- D.$$\frac{33}{2^{27}}$$
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