JEE Math Practice Question
A biased die is marked with numbers 2, 4, 8, 16, 32, 32 on its faces and the probability of getting a face with mark n is $${1 \over n}$$. If the die is thrown thrice, then the probability, that the sum of the numbers obtained is 48, is :
- A.$${7 \over {{2^{11}}}}$$
- B.$${7 \over {{2^{12}}}}$$
- C.$${3 \over {{2^{10}}}}$$
- D.$${{13} \over {{2^{12}}}}$$
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