JEE Math Practice Question
Let in a Binomial distribution, consisting of 5 independent trials, probabilities of exactly 1 and 2 successes be 0.4096 and 0.2048 respectively. Then the probability of getting exactly 3 successes is equal to :
- A.$${{40} \over {243}}$$
- B.$${{128} \over {625}}$$
- C.$${{80} \over {243}}$$
- D.$${{32} \over {625}}$$
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