JEE Math Practice Question
If the system of equations $$ \begin{aligned} & (\lambda-1) x+(\lambda-4) y+\lambda z=5 \\ & \lambda x+(\lambda-1) y+(\lambda-4) z=7 \\ & (\lambda+1) x+(\lambda+2) y-(\lambda+2) z=9 \end{aligned}$$ has infinitely many solutions, then $\lambda^2+\lambda$ is equal to
- A.20
- B.10
- C.6
- D.12
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