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JEE Math Practice Question

If $$\mathrm{A}=\frac{1}{5 ! 6 ! 7 !}\left[\begin{array}{ccc}5 ! & 6 ! & 7 ! \\ 6 ! & 7 ! & 8 ! \\ 7 ! & 8 ! & 9 !\end{array}\right]$$, then $$|\operatorname{adj}(\operatorname{adj}(2 \mathrm{~A}))|$$ is equal to :

  1. A.$$2^{12}$$
  2. B.$$2^{20}$$
  3. C.$$2^{8}$$
  4. D.$$2^{16}$$

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