JEE Math Practice Question
$$\left|\begin{array}{ccc}x+1 & x & x \\ x & x+\lambda & x \\ x & x & x+\lambda^{2}\end{array}\right|=\frac{9}{8}(103 x+81)$$, then $$\lambda, \frac{\lambda}{3}$$ are the roots of the equation :
- A.$$4 x^{2}+24 x-27=0$$
- B.$$4 x^{2}-24 x+27=0$$
- C.$$4 x^{2}-24 x-27=0$$
- D.$$4 x^{2}+24 x+27=0$$
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