JEE Math Practice Question
Let for $$A = \left[ {\begin{matrix} 1 & 2 & 3 \\ \alpha & 3 & 1 \\ 1 & 1 & 2 \\ \end{matrix} } \right],|A| = 2$$. If $$\mathrm{|2\,adj\,(2\,adj\,(2A))| = {32^n}}$$, then $$3n + \alpha $$ is equal to
- A.11
- B.9
- C.12
- D.10
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