JEE Math Practice Question
Let the system of linear equations $$x+y+kz=2$$ $$2x+3y-z=1$$ $$3x+4y+2z=k$$ have infinitely many solutions. Then the system $$(k+1)x+(2k-1)y=7$$ $$(2k+1)x+(k+5)y=10$$ has :
- A.unique solution satisfying $$x-y=1$$
- B.infinitely many solutions
- C.no solution
- D.unique solution satisfying $$x+y=1$$
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