JEE Math Practice Question
If the system of equations $$\alpha$$x + y + z = 5, x + 2y + 3z = 4, x + 3y + 5z = $$\beta$$ has infinitely many solutions, then the ordered pair ($$\alpha$$, $$\beta$$) is equal to :
- A.(1, $$-$$3)
- B.($$-$$1, 3)
- C.(1, 3)
- D.($$-$$1, $$-$$3)
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