JEE Math Practice Question
Let A(a, 0), B(b, 2b + 1) and C(0, b), b $$\ne$$ 0, |b| $$\ne$$ 1, be points such that the area of triangle ABC is 1 sq. unit, then the sum of all possible values of a is :
- A.$${{ - 2b} \over {b + 1}}$$
- B.$${{2b} \over {b + 1}}$$
- C.$${{2{b^2}} \over {b + 1}}$$
- D.$${{ - 2{b^2}} \over {b + 1}}$$
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