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JEE Math Practice Question

Let $$A = \left( {\begin{matrix} {[x + 1]} & {[x + 2]} & {[x + 3]} \\ {[x]} & {[x + 3]} & {[x + 3]} \\ {[x]} & {[x + 2]} & {[x + 4]} \\ \end{matrix} } \right)$$, where [t] denotes the greatest integer less than or equal to t. If det(A) = 192, then the set of values of x is the interval :

  1. A.[68, 69)
  2. B.[62, 63)
  3. C.[65, 66)
  4. D.[60, 61)

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