JEE Math Practice Question
The solutions of the equation $$\left| {\begin{matrix} {1 + {{\sin }^2}x} & {{{\sin }^2}x} & {{{\sin }^2}x} \\ {{{\cos }^2}x} & {1 + {{\cos }^2}x} & {{{\cos }^2}x} \\ {4\sin 2x} & {4\sin 2x} & {1 + 4\sin 2x} \\ \end{matrix} } \right| = 0,(0 < x < \pi )$$, are
- A.$${\pi \over {12}},{\pi \over 6}$$
- B.$${\pi \over 6},{{5\pi } \over 6}$$
- C.$${{5\pi } \over {12}},{{7\pi } \over {12}}$$
- D.$${{7\pi } \over {12}},{{11\pi } \over {12}}$$
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