JEE Math Practice Question
If $$A = \left( {\begin{matrix} 0 & {\sin \alpha } \\ {\sin \alpha } & 0 \\ \end{matrix} } \right)$$ and $$\det \left( {{A^2} - {1 \over 2}I} \right) = 0$$, then a possible value of $$\alpha$$ is :
- A.$${\pi \over 4}$$
- B.$${\pi \over 6}$$
- C.$${\pi \over 2}$$
- D.$${\pi \over 3}$$
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