JEE Math Practice Question
If $$\left| {\begin{matrix} {a - b - c} & {2a} & {2a} \\ {2b} & {b - c - a} & {2b} \\ {2c} & {2c} & {c - a - b} \\ \end{matrix} } \right|$$ = (a + b + c) (x + a + b + c)2, x $$ \ne $$ 0, then x is equal to :
- A.–2(a + b + c)
- B.2(a + b + c)
- C.abc
- D.–(a + b + c)
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