JEE Math Practice Question

If $$\left[ {\begin{matrix} 1 & 1 \\ 0 & 1 \\ \end{matrix} } \right]\left[ {\begin{matrix} 1 & 2 \\ 0 & 1 \\ \end{matrix} } \right]$$$$\left[ {\begin{matrix} 1 & 3 \\ 0 & 1 \\ \end{matrix} } \right]$$....$$\left[ {\begin{matrix} 1 & {n - 1} \\ 0 & 1 \\ \end{matrix} } \right] = \left[ {\begin{matrix} 1 & {78} \\ 0 & 1 \\ \end{matrix} } \right]$$, then the inverse of $$\left[ {\begin{matrix} 1 & n \\ 0 & 1 \\ \end{matrix} } \right]$$ is

1. A.$$\left[ {\begin{matrix} 1 & { 0} \\ {12} & 1 \\ \end{matrix} } \right]$$
2. B.$$\left[ {\begin{matrix} 1 & { 0} \\ {13} & 1 \\ \end{matrix} } \right]$$
3. C.$$\left[ {\begin{matrix} 1 & { - 13} \\ 0 & 1 \\ \end{matrix} } \right]$$
4. D.$$\left[ {\begin{matrix} 1 & { - 12} \\ 0 & 1 \\ \end{matrix} } \right]$$