JEE Math Practice Question
Suppose $$\theta \in\left[0, \frac{\pi}{4}\right]$$ is a solution of $$4 \cos \theta-3 \sin \theta=1$$. Then $$\cos \theta$$ is equal to :
- A.$$\frac{6-\sqrt{6}}{(3 \sqrt{6}-2)}$$
- B.$$\frac{4}{(3 \sqrt{6}+2)}$$
- C.$$\frac{6+\sqrt{6}}{(3 \sqrt{6}+2)}$$
- D.$$\frac{4}{(3 \sqrt{6}-2)}$$
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