JEE Math Practice Question
The value of $${\cos ^3}\left( {{\pi \over 8}} \right)$$$${\cos}\left( {{3\pi \over 8}} \right)$$+$${\sin ^3}\left( {{\pi \over 8}} \right)$$$${\sin}\left( {{3\pi \over 8}} \right)$$ is :
- A.$${1 \over {\sqrt 2 }}$$
- B.$${1 \over 2}$$
- C.$${1 \over 4}$$
- D.$${1 \over 2{\sqrt 2 }}$$
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