JEE Math Practice Question
If $$5\left( {{{\tan }^2}x - {{\cos }^2}x} \right) = 2\cos 2x + 9$$, then the value of $$\cos 4x$$ is :
- A.$${1 \over 3}$$
- B.$${2 \over 9}$$
- C.$$ - {7 \over 9}$$
- D.$$ - {3 \over 5}$$
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