JEE Math Practice Question
If $$u = \sqrt {{a^2}{{\cos }^2}\theta + {b^2}{{\sin }^2}\theta } + \sqrt {{a^2}{{\sin }^2}\theta + {b^2}{{\cos }^2}\theta } $$ then the difference between the maximum and minimum values of $${u^2}$$ is given by :
- A.$${\left( {a - b} \right)^2}$$
- B.$$2\sqrt {{a^2} + {b^2}} $$
- C.$${\left( {a + b} \right)^2}$$
- D.$$2\left( {{a^2} + {b^2}} \right)$$
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