JEE Chemistry Practice Question
Match the electronic configurations in List-I with appropriate metal complex ions in List-II and choose the correct option. [Atomic Number: $\mathrm{Fe}=26, \mathrm{Mn}=25$, $\mathrm{Co}=27$ ] List-I (P) $t_{2 g}^{6} e_{g}^{0}$ (Q) $t_{2 g}^{3} e_{g}^{2}$ (R) $\mathrm{e}^{2} \mathrm{t}_{2}^{3}$ (S) $t_{2 g}^{4} e_{g}^{2}$ List-II (1) $\left[\mathrm{Fe}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ (2) $\left[\mathrm{Mn}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}$ (3) $\left[\mathrm{Co}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}$ (4) $\left[\mathrm{FeCl}_{4}\right]^{-}$ (5) $\left[\mathrm{CoCl}_{4}\right]^{2-}$
- A.$\mathrm{P} \rightarrow 1$; Q $\rightarrow 4$; $\mathrm{R} \rightarrow 2$; $\mathrm{S} \rightarrow 3$
- B.$\mathrm{P} \rightarrow 1 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 4 ; \mathrm{S} \rightarrow 5$
- C.$\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 5 ; \mathrm{S} \rightarrow 1$
- D.$\mathrm{P} \rightarrow 3 ; \mathrm{Q} \rightarrow 2 ; \mathrm{R} \rightarrow 4$; $\mathrm{S} \rightarrow 1$
Want to know if you got it right?
Answer this and thousands more real JEE previous-year questions free, get graded instantly, and climb the global ranked leaderboard.
Practice JEE free →More JEE Chemistry questions
- The mole fraction of a solute in a solution is 0.1 . At 298 \mathrm{~K}, molarity of this …
- The diffusion coefficient of an ideal gas is proportional to its mean free path and mean s…
- In neutral or faintly alkaline solution, 8 moles of permanganate anion quantitatively oxid…
- A crystalline solid of a pure substance has a face-centred cubic structure with a cell edg…
- The conductance of a 0.0015 \mathrm{M} aqueous solution of a weak monobasic acid was deter…
- What is the sum of the number of lone pairs of electrons on each central atom in the follo…
- Among \mathrm{H}_{2}, \mathrm{He}_{2}{ }^{+}, \mathrm{Li}_{2}, \mathrm{Be}_{2}, \mathrm{~B…
- The ammonia prepared by treating ammonium sulphate with calcium hydroxide is completely us…