JEE Chemistry Practice Question

Plotting $1 / \Lambda_{\mathrm{m}}$ against $\mathrm{c} \Lambda_{\mathrm{m}}$ for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of $\mathrm{P}$ and slope of $\mathrm{S}$. The ratio $\mathrm{P} / \mathrm{S}$ is $\left[\Lambda_{\mathrm{m}}=\right.$ molar conductivity $\Lambda_{\mathrm{m}}^{\mathrm{o}}=$ limiting molar conductivity $\mathrm{c}=$ molar concentration $\mathrm{K}_{\mathrm{a}}=$ dissociation constant of $\mathrm{HX}$ ]

1. A.$\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}$
2. B.$\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}} / 2$
3. C.$2 \mathrm{~K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}$
4. D.$1 /\left(\mathrm{K}_{\mathrm{a}} \Lambda_{\mathrm{m}}^{\mathrm{o}}\right)$