JEE Math Practice Question
Let $X=\left\{(x, y) \in \mathbb{Z} \times \mathbb{Z}: \frac{x^{2}}{8}+\frac{y^{2}}{20}<1\right.$ and $\left.y^{2}<5 x\right\}$. Three distinct points $P, Q$ and $R$ are randomly chosen from $X$. Then the probability that $P, Q$ and $R$ form a triangle whose area is a positive integer, is
- A.$\frac{71}{220}$
- B.$\frac{73}{220}$
- C.$\frac{79}{220}$
- D.$\frac{83}{220}$
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