JEE Chemistry Practice Question

The reaction of $\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}$ and $\mathrm{NaCl}$ in water produces a precipitate that dissolves upon the addition of $\mathrm{HCl}$ of appropriate concentration. The dissolution of the precipitate is due to the formation of

1. A.$\mathrm{PbCl}_{2}$
2. B.$\mathrm{PbCl}_{4}$
3. C.$\left[\mathrm{PbCl}_{4}\right]^{2-}$
4. D.$\left[\mathrm{PbCl}_{6}\right]^{2-}$